SqlCriteria - изменен расчет кол-ва записей при использовании GROUP BY
(In this thread: http://www.cyberforum.ru/mysql/thread681915.html I have solution for my problem - USE COUNT(DISTINCT pid))
This commit is contained in:
@ -84,15 +84,22 @@ class SqlCriteria
|
||||
{
|
||||
$this->defineJoinExpressions($select);
|
||||
$sql_expression_backup = $this->sql_expression;
|
||||
$group_by_backup = $this->group_by;
|
||||
$select_parent_query = 'COUNT(*) as count';
|
||||
$default_select = '*';
|
||||
if ($this->group_by) {
|
||||
$default_select = 'DISTINCT ' . $this->group_by[0];
|
||||
}
|
||||
$this->group_by = [];
|
||||
if (!$this->sql_expression) {
|
||||
$this->sql_expression = 'SELECT COUNT(' . ($select ? $select : '*') . ') as count FROM :table';
|
||||
$this->sql_expression = 'SELECT COUNT(' . ($select ? $select : $default_select) . ') as count FROM :table';
|
||||
$select_parent_query = 'x.count';
|
||||
} else {
|
||||
$this->sql_expression = preg_replace('#SELECT.+FROM#i', 'SELECT COUNT(' . ($select ? $select : '*') . ') as count FROM', $this->sql_expression);
|
||||
$this->sql_expression = preg_replace('#SELECT.+FROM#i', 'SELECT COUNT(' . ($select ? $select : $default_select) . ') as count FROM', $this->sql_expression);
|
||||
}
|
||||
$count = $this->model->count($select_parent_query, $this->where, null, $this->group_by, $this->sql_expression, $this->sql_expression_params)->fetchField('count');
|
||||
$this->sql_expression = $sql_expression_backup;
|
||||
$this->group_by = $group_by_backup;
|
||||
return $count;
|
||||
}
|
||||
|
||||
|
Reference in New Issue
Block a user